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- Thread starter Benny
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Is x function of y ? is y function of x ? Or both x and y function of some other argument ?

Your are gonna need to be a bit more specific here

marlon

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saltydog

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Benny said:

Hey Benny, you got this? It's a particular form of the Riccati Equation right?

[tex]y^{'}+Q(x)y+R(x)y^2=P(x)[/tex]

so yours is:

[tex]y^{'}-y^2=x^2[/tex]

Thus make the substitution:

[tex]y=\frac{u^{'}}{-u}[/tex]

Turn the crank and get:

[tex]u^{''}-x^2u=0[/tex]

Then solve via power series, then take the derivative, form the quotient, then a plot. Put it all into Mathematica and back-substitute to make sure it's correct, then compare with numerical results. Or just do what you want.

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